1,2-dichlorocyclopentane xrightarrow{1 text{ | vedclass

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Question

(A) The reaction of $1,2-dichlorocyclopentane$ with $1 	ext{ equivalent}$ of $Mg$ in ether leads to the formation of a Grignard reagent intermediate

Vedclass · Accepted Answer

$1-$chloro$-2-$deuterocyclopentane

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(A) The reaction of $1,2-dichlorocyclopentane$ with $1 	ext{ equivalent}$ of $Mg$ in ether leads to the formation of a Grignard reagent intermediate $X$ $(2-chlorocyclopentylmagnesium 	ext{ chloride})$. $X$ is $C_5H_8ClMgCl$. When this intermediate $X$ is treated with $D_2O$,the $MgCl$ group is replaced by a deuterium atom $(D)$. Therefore,the final product $Y$ is $1-chloro-2-deuterocyclopentane$.

$1,2-dichlorocyclopentane$ $\xrightarrow{1 \text{ equivalent } Mg, \text{ ether}} X$ $\xrightarrow{D_2O} Y;$
$Y$ is:

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$1,2-dichlorocyclopentane$ $\xrightarrow{1 \text{ equivalent } Mg, \text{ ether}} X$ $\xrightarrow{D_2O} Y;$$Y$ is: